Reason No. 2 Cleveland Browns should not trade Denzel Ward
The compensation is not guaranteed
When big names are traded in the NFL, the biggest compensation is typically draft picks. We all know that Andrew Berry values draft picks, but trading Ward for draft capital might not work out in the long run.
One thing that could intrigue Berry to pull the trigger on sending Ward elsewhere is to replenish the draft capital he gave up in order to get Deshaun Watson from the Texans. Surely, the compensation wouldn’t be close to the same as what the Texans received, so it’s not like he would get back many first-round picks.
Even if the haul was good and regardless of how well Berry drafts, the players selected are not guaranteed to succeed in the NFL. Any given player could be deemed as the next big NFL superstar, but could ultimately not pan out due to a plethora of reasons.
One of those reasons could be the player is not a good fit schematically. While the Browns do have good coaching personnel and a smart front office, that doesn’t mean they will hit on every draft pick.
The NFL Draft is a giant crapshoot with a lot of uncertainties. Sure, some players are going to make immediate impacts in their rookie seasons, but not all of them will. And sure, the cap hit will be a lot less than paying Ward, but how long can you trade good players for prospects and be successful? Trading Ward for draft capital would not be a surefire way to get back the value of Ward.